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The reaction of hydrochloric acid (HCl) with ammonia (NH3) is described by the equation:


HCl + NH3 → NH4Cl


A student is titrating 50 mL of 0.32 M NH3 with 0.5 M HCl. How much hydrochloric acid must be added to react completely with the ammonia?


A. 6.4 mL

B. 16.0 mL

C. 32.0 mL

D. 50.0 mL

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Respuesta :

Answer : The correct option is, (C) 32.0 mL

Explanation :

Formula used :

[tex]M_1V_1=M_2V_2[/tex]

where,

[tex]M_1\text{ and }V_1[/tex] are the initial molarity and volume of NH₃.

[tex]M_2\text{ and }V_2[/tex] are the final molarity and volume of HCl.

We are given:

[tex]M_1=0.32M\\V_1=50mL\\M_2=0.5M\\V_2=?[/tex]

Now put all the given values in above equation, we get:

[tex]0.32M\times 50mL=0.5M\times V_2\\\\V_2=32.0mL[/tex]

Hence, the volume of hydrochloric acid added to react completely with the ammonia must be, 32.0 mL

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