Complete Question
The complete question is is shown on the first uploaded
Answer:
The elastic potential energy at point B is  [tex]PE_{elastic} = 50J[/tex]
The kinetic energy at point D is [tex]KE = 75J[/tex]
Explanation:
Looking at the given point we can observe that mechanically energy(i.e potential and kinetic energy ) is conserved and it value is [tex]E_ {m} = 100J[/tex]
   So at point B
      [tex]E_{m} = PE_{elastic} +KE[/tex]
      [tex]100 = PE_{elastic} + KE[/tex]
  KE at point B is  50J
So   [tex]PE_{elastic} = 100 - 50 = 50J[/tex]
   Now at point D
     [tex]E_{m} = PE_{elastic} +KE[/tex]
  [tex]PE_{elastic}[/tex] at point D is 25J
 So  [tex]KE = 100 - 25 = 75J[/tex]
