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You have a culture of yeast that is at a concentration of 6.74 x 10⁶ cells/ml. You dilute the sample 1:100, and then 1:100 again, and finally you dilute the sample an additional 1:3. You add 0.1 ml of the final dilution to a spread plate.
Assuming that most of the cells in the original culture were living, how many CFUs do you expect to count on your spread plate the next day?

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Respuesta :

ajeigbeibraheem

Answer:

22 cells

Explanation:

Given that:

The concentration of numbers of cells = 6.74 x 10⁶ cells/ml

Dilution stages includes =  1:100  ;     1:100    &        1:3

The consecutive dilution stages can be calculated as:

= [tex](6.74*10^6)*(\frac{1}{100})(\frac{1}{100})(\frac{1}{3})[/tex]

=  222.42 cells/ml

= 2.22 × 10² cells/ml

So after addition  0.1 ml of the final dilution to a spread plate, the number of CFUs ( Colony forming units) we expect to count will be:

= (2.22 × 10² cells/ml)(0.1 ml)

= 22.2 cells

≅ 22 cells

∴ the number of  CFUs we expect to count on our spread plate the next day = 22 cells

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