A 0.25 kg ideal harmonic oscillator has a total mechanical energy of 9.8 J. If the oscillation amplitude is 20.0 cm, what is the oscillation frequency?a. 4.6 Hz b. 1.4 Hz c. 2.3 Hz d. 3.2 Hz

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Answer:

7.04 Hz

Explanation:

x(t) = A cos(wt)

v(t) = - wA sin (wt)

Vmax = wA

E = 1/2 * m * (Vmax)^2

E = 1/2*m*(wA)^2

[tex]w = \frac{1}{A} \sqrt{\frac{2E}{m} }[/tex]

f = w/ 2*pi

[tex]f = \frac{1}{2*pi*A}*\sqrt{\frac{2E}{m} } \\f = \frac{1}{2 * pi * 0.2}*\sqrt{\frac{2(9.8)}{0.25} } \\f = 7.04 Hz[/tex]