Answer:
P = 7.28 N.s
Explanation:
given,
initial momentum of cue ball in x- direction,Pā = 9 N.s
momentum of nine ball in Ā x- Ā direction, Pā = 2 N.s
momentum in perpendicular direction i.e. y - direction,P'ā = 2 N.s
momentum of the cue after collision = ?
using conservation of momentum
in x- direction
Pā + p = x Ā + Pā
p is the initial momentum of the nine balls which is equal to zero.
9 + 0 Ā = x Ā + 2
x = 7 N.s
momentum in x-direction.
equating along y-direction
P'ā + p = y + P'ā
0 + 0 = y + 2
y = -2 N.s
the momentum of the cue ball after collision is equal to resultant of the momentum .
[tex]P = \sqrt{x^2+y^2}[/tex]
[tex]P = \sqrt{7^2+(-2)^2}[/tex]
Ā Ā Ā P = 7.28 N.s
the momentum of the cue ball after collision is equal to P = 7.28 N.s
