Answer: Mass of one mole of viruses in grams is [tex]54\times 10^{8}[/tex]
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
Given : One virus has mass of = [tex]9.0\times 10^{-12}mg=9.0\times 10^{-15}g[/tex] [tex]1mg=10^{-3}g[/tex]
One mole of virus [tex]6.023\times 10^{23}[/tex] has mass of = [tex]\frac{9.0\times 10^{-15}}{1}\times 6.023\times 10^{23}=54\times 10^{8}g[/tex]
Thus mass of one mole of viruses in grams is [tex]54\times 10^{8}[/tex]
