
Answer:
A) Â R = (200 i ^ + 100 j ^ + 30k ^) m , B) Â Â L = 223.61 m , C) Â R = 225.61 m
Explanation:
Part A
This is a vector summing exercise, let's take a Reference System where the z axis corresponds to the height (flights), the x axis is the East - West and the y axis corresponds to the North - South.
Let's write the displacements
Descending from the apartment
10 flights of 3 m each, the total descent is 30 m
        Z = 30 k ^ m
Offset at street level
      L1 = 0.2 i ^ km
      L2 = 0.1 j ^ km
Let's reduce everything to the SI system
     L1 = 0.2 * 1000 = 200 i ^ m
     L2 = 100 j ^ m
The distance traveled is
     R = (200 i ^ + 100 j ^ + 30k ^) m
Part B
The horizontal distance traveled can be found with the Pythagorean theorem for the coordinates in the plane
        L² = x² + y²
        L = √ (200² + 100²)
        L = 223.61 m
Part C
The magnitude of travel, let's use the Pythagorean theorem for the sum
       R² = x² + y² + z²
       R = √ (30² + 200² + 100²)
       R = 225.61 m