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A 2.0cm3 air bubble is released from the sandy bottom of a warm, shallow sea, where the gauge pressure is 1.2atm . The bubble rises slowly enough that the air inside remains at the same constant temperature as the water.What is the volume of the bubble as it reaches the surface?

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Respuesta :

Answer:

V2 = P1×V1/P2

V2 = 4.4cm3

Explanation:

Applying Boyle's law

P1×V1 = P2×V2

V2 = P1×V1/P2

Where;

V1 = initial volume of air bubble = 2.0cm3

V2 = final volume of air bubble

P1 = initial pressure of air bubble = 1.2 + 1 atm = 2.2 atm

(Absolute pressure = guage pressure + atmospheric pressure)

P2 = final pressure of air bubble = 1 atm

V2 = 2.0× 2.2/1.0

V2 = 4.4cm3

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