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A 3.2-kg block is hanging stationary from the end of a vertical spring that is attached to the ceiling. The elastic potential energy of this spring-block system is 1.8 J. What is the elastic potential energy of the system when the 3.2-kg block is replaced by a 5.0-kg block?

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princessesther2011

Answer:

2.94J

Explanation:

Potential Energy (P.E) = mass(m) × acceleration due to gravity (g) × height (h)

P.E = mgh

P.E=1.8J, m=3.2kg, g=9.8m/s^2

h = P.E/mg = 1.8/(3.2×9.8) = 1.8/31.36 = 0.06m

P.E = 5×9.8×0.06 = 2.94J

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