State whether each of the following changes would make a confidence interval wider or narrower.โ€‹ (Assume that nothing elseโ€‹ changes.) a. Changing from a 95โ€‹% confidence level to a 99โ€‹% confidence level. b. Changing from a sample size of 15 to a sample size of 350. c. Changing from a standard deviation of 15 pounds to a standard deviation of 20 pounds.

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Answer:

Step-by-step explanation:

The formula for determining confidence interval is expressed as

Confidence interval

= mean ยฑ z ร— s/ โˆšn

Where

z is the value of the z score

s = standard deviation

n = sample size

a) The 95โ€‹% confidence level has a z value of 1.96

The 99โ€‹% confidence level has a z value of 2.58

Since 99โ€‹% confidence level z value is greater than 95โ€‹% confidence level z value, if we input it into the formula, it will result to a higher confidence interval. So changing from a 95โ€‹% confidence level to a 99โ€‹% confidence level would make a confidence interval wider.

b) The โˆš15 is smaller than the โˆš350. This means that if we make use of the formula, โˆš350 will give a lower confidence interval than that of โˆš15. Therefore, the confidence interval would be narrower changing from a sample size of 15 to a sample size of 350.

c) Applying the formula, a standard deviation of 15 pounds would result to a lower confidence interval than a standard deviation of 20 pounds. Therefore, the confidence interval would be wider changing from a standard deviation of 15 pounds to a standard deviation of 20 pounds.