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A sample of helium has a volume of 5 liters and a pressure of 699 mmHg. If the final volume is 5.7 Liters, its final temperature 303 K, and the final pressure 800 mmHg, what was the initial temperature of helium?

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Answer:

The initial temperature of helium was T1 = 232.23 K

Explanation:

Given data:

Initial volume V1 = 5 L

Initial pressure P1 = 699 mmHg

Final pressure P2 = 800 mmHg

Final volume V2 = 5.7 L

Final temperature T2= 303 K

Initial temperature T1 = ?

Solution:

Formula:

P1V1/T1 = P2V2/T2

T1 = T2 × P1V1/P2V2

T1 = 303 K × 699 mmHg × 5 L / 800 mmHg × 5.7 L

T1 = 1058985/ 4560

T1 = 232.23 K

initial temperature of helium was 232.23 k.

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