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A wire 2.80 m in length carries a current of 7.40 A in a region where a uniform magnetic field has a magnitude of 0.490 T. Calculate the magnitude of the magnetic force on the wire assuming the following angles between the magnetic field and the current.

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Answer:

Explanation:

L = 2.80 m, i = 7.40 A, B = 0.490 T

The magnetic force acting on the wire is given by

F = B i L Sinθ

F = 0.490 x 7.40 x 2.80 x Sinθ

F = 10.153 x Sinθ

Here, substitute the value of angle θ and get the value of force.

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