When a 1.50V battery is shorted by a copper wire whose resistance can be ignored, the current through the copper wire is 2.75 A. What is the internal resistance of the battery?

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Answer:

Internal resistance = 0.545 ohm

Explanation:

As per ohm's law we know that

[tex]V = iR[/tex]

here we know that

i = electric current = 2.75 A

V = potential difference = 1.50 Volts

now from above equation we have

[tex]1.50 = 2.75 ( R)[/tex]

now we have

[tex]R = \frac{1.50}{2.75}[/tex]

[tex]R = 0.545 ohm[/tex]