Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = 4x^2 + 3x + 4, [βˆ’1, 1]

No, f is continuous on [βˆ’1, 1] but not differentiable on (βˆ’1, 1).
No, f is not continuous on [βˆ’1, 1].
Yes, f is continuous on [βˆ’1, 1] and differentiable on (βˆ’1, 1) since polynomials are continuous and differentiable on .
There is not enough information to verify if this function satisfies the Mean Value Theorem.
Yes, it does not matter if f is continuous or differentiable; every function satisfies the Mean Value Theorem.

Relax