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The given expression will be undefined for x = -4 and x = -2.

The given expression will be undefined if the denominator equal to 0.

It means:

[tex]x^2+6x+8=0\\ (x+4)(x+2)=0\\ x=-4,-2[/tex]

Hence, the given expression will be undefined for x = -4 and x = -2.

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