Find the particular solution to y " = 2sin(x) given the general solution y = −2sin(x) + Ax + B and the initial conditions y of pi over 2 equals 0 and y prime of pi over 2 equals negative 2.

−2sin(x) + 2

−2sin(x) − 2x + π + 2

−2sin(x) − 2x + 2π

−2sin(x) − 2x + π