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How many moles of sulfuric acid (H2SO4) are needed to react completely with 6.8 moles of lithium hydroxide (LiOH)?


2LiOH + H2SO4 → Li2SO4 + 2H2O


A) 3.4 mol H2SO4

B) 6.8 mol H2SO4

C) 10.2 mol H2SO4

D) 13.6 mol H2SO4

answer: A) 3.4 mol H2SO4

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superman1987

Answer:

A) 3.4 mole of Hâ‚‚SOâ‚„.

Explanation:

  • From the stichiometry of the reaction: 2 LiOH + Hâ‚‚SOâ‚„ → Liâ‚‚SOâ‚„ + 2 Hâ‚‚O
  • It is clear that 2.0 moles of LiOH reacts with 1.0 mole of Hâ‚‚SOâ‚„ to produce 1.0 mole of Liâ‚‚SOâ‚„ and 2.0 moles of Hâ‚‚O.

Using cross multiplication:

1.0 mole of H₂SO₄ reacts completely with → 2.0 moles of LiOH

??? mole of H₂SO₄ are needed to react completely with → 6.8 moles of LiOH

  • The number of moles of Hâ‚‚SOâ‚„ = (1.0 x 6.8) / (2.0) = 3.4 mole of Hâ‚‚SOâ‚„.

Answer:

The answer is A (3.4 mol H2SO4)

Explanation:

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