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A person drives an automobile with a mass of 450 kilograms at a velocity of 26 meters per second. The driver accelerates to a velocity of 30 meters per second. The difference in the automobileā€™s kinetic energy between the two velocities is joules. You may use the calculator.

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georgestirban

Ecā‚=mvā‚Ā²/2=450*26Ā²/2=225*676=152100 J

Ecā‚‚=mvā‚‚Ā²/2=450*30Ā²/2=225*900=202500 J

Ī”Ec=Ecā‚‚-Ecā‚=202500-152100=50.4 kJ

Eduard22sly

The difference in the kinetic energy of the automobile is 50400 J.

To answer the question, we shall determine the kinetic energy of the automobile in each case. This can be obtained as illustrated below:

Case 1:

Mass (m) = 450 Kg

Velocity (vā‚) = 26 m/s

Kinetic energy (KEā‚) =?

KEā‚ = Ā½mvā‚Ā²

KEā‚ = Ā½ Ɨ 450 Ɨ 26Ā²

KEā‚ = 225 Ɨ 676

KEā‚ = 152100 J

Case 2:

Mass (m) = 450 Kg

Velocity (vā‚‚) = 30 m/s

Kinetic energy (KEā‚‚) =?

KEā‚‚ = Ā½mvā‚‚Ā²

KEā‚‚ = Ā½ Ɨ 450 Ɨ 30Ā²

KEā‚‚ = 225 Ɨ 900

KEā‚‚ = 202500 J

Finally, we shall determine the difference in the kinetic energy of the automobile. This can be obtained as illustrated below:

Kinetic energy of case 1 (KEā‚) = 152100 J

Kinetic energy of case 2 (KEā‚‚) = 202500 J

Difference =?

Difference = KEā‚‚ ā€“ KEā‚

Difference = 202500 ā€“ 152100

Difference = 50400 J

Therefore, the difference in the kinetic energy of the automobile is 50400 J

Learn more: https://brainly.com/question/24350652

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