Relax

Respuesta :

gmany

Look at the picture.

The area of the trapezoid:

[tex]A_T=\dfrac{1}{2}(15+7+5)\cdot4=27\cdot2=54\ in^2[/tex]

The area of the rectangle:

[tex]A_R=5\cdot6=30\ in^2[/tex]

The area of figure:

[tex]A=A_T+A_R\to A=54+30=84\ in^2[/tex]

Ver imagen gmany

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