jaredlewq
jaredlewq jaredlewq
  • 25-07-2018
  • Mathematics
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if [tex] (x+y)^{2} [/tex]=36 and xy= -7, findthe value of [tex] x^{2}+y^{2} [/tex]

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DeanR
DeanR DeanR
  • 25-07-2018

[tex](x + y)^2 = 36[/tex]


[tex]x^2 + 2xy + y^2 = 36[/tex]


[tex]x^2+ y^2 = 36 - 2xy = 36- 2(-7)= 36+14=50[/tex]


Answer: 50




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