claireee420
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How much force is exerted on a 60 kg person who hits an airbag at 45 m/s if the impact takes 0.65 seconds? Please give me an explanation as to how you got the answer if you can :)

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Respuesta :

     We must rewrite the Newton's Second Law:

[tex]F_{av}=ma_{av}~~~~"av"~means~average \\ F_{av}=m (\frac{\Delta v}{\Delta t} )~~Also~known~as~Impulse~Theorem[/tex]
 
     Applying in the question:

[tex]F=60( \frac{45}{0.65} ) \\ \boxed {F \approx 4.15~kN}[/tex]

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