In four years Cranston’s age will be the same as Terrill’s age is now. In two years time, Terrill will be twice as old as Cranston. Find their ages now.

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 c + 4 = t 
t + 2 = 2c 
c + 4 = 2c – 2 
c = 2 
t = 6


or

c = t - 4....................................(1) 


in 2 years we have: 

t + 2 = 2(c + 2) 

i.........e......... t + 2 = 2c + 4 

=> t - 2c = 2...........................(2) 

(1) into (2) for c gives: 

t - 2(t - 4) = 2 

i.........e......... 8 - t = 2 

so, t = 6 and c = 2 

therefore, terrill is 6 and cranston is 2 

and, in 2 years time they shall be 8 and 4....................................i..... terrill being twice cranston's age 

i lost myself the first time i solved it 




Answer:

Cranston's Age: 2 years

Terril's Age: 6 years

Step-by-step explanation:

c = Cranston

t = Terril

Information we have:

c + 4 = t

t + 2 = 2c

So, if Cranston is 2 and Terril is 6, it's true as c + 4 (2 + 4) is 6 and When Cranston and Terril age 2 years, Cranston will be 4 and Terril will be 8, so Terril will be twice of Cranston's age.

*A lot of people forget the part where Cranston will ALSO age, so they get t = 10 and c = 6