a) we know that T - mg = mv^2/r The net forces equal the mass times the centripetal acceleration So T=50 N m=3 kg r=0.60 m v = sqrt((T-mg)r/m) = sqrt((50-(3*9.8))*(.60)/3) = 2.03 m/s
the answer part a) is 2.03 m/s
b) At the top the equation becomes T+mg=mv^2/r but here the critical speed occurs when T = 0 so the critical speed is v = sqrt(rg) = sqrt (.60*9.80) = 2.42 m/s
