helenmann2016 helenmann2016

26-11-2017
Mathematics

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(dH/dt)=k(68-H) find the general solution for the differential equation

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MathisLif3 MathisLif3

26-11-2017

dH/dt=k(68-H)
1/(68-H)dH=kt assuming k is a constant
ln|68-H|=kt+C (*)
we have all H satisfying (*)

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