orianne9238 orianne9238

22-03-2024
Mathematics

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It is given that m/AOB = 66° By the m/BOC m/AOC+m/COD = m/EOF= == 42° and m EOF = 66° 66° By the V ZEOF ZBOC. Therefore, mZAOC = 108° and by the = 180° After application of the V m/COD = 72 =

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