
Answer:
Step-by-step explanation:
Given that Ian factored
[tex]12x^3y^3 - 24x^2y^3[/tex]
as
[tex]6xy(2x^2y^2 - 4xy^2).[/tex]
We find that inside still there are common factors for the two terms.
We can find 2 as common factor and for x, the term x and for y it is y^2
So correct factorisation would be
[tex]12x^2y^3(x-2)[/tex]