The formula for calculating the amount of heat energy absorbed is given as:
[tex]Q=mc\triangle t[/tex]Given the following
• mass m = 50.0g
,• Heat energy Q = 7490 Joules
,• change in temperature = 80 -10= 70 degrees celsius
Substitute
[tex]\begin{gathered} 7490=50\times c\times70 \\ c=\frac{7490}{3500} \\ c=2.14J\text{/}g^oC \end{gathered}[/tex]Hence the specific heat capacity of methanol is 2.14J/gC
