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a student wants to measure the height of a tree. from a point on the ground 10 feet away from the base of the tree, the angle of elevation to the top of the tree is 65angle. what is the height of the tree to the nearest tenth of a foot?

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Answer:

Step-by-step explanation:

Use SOH CAH TOA to recall how the trig functions fit on a triangle

SOH: Sin(Π€)= Opp / Hyp

CAH: Cos(Π€)= Adj / Hyp

TOA: Tan(Π€) = Opp / Adj

Tan(65) = Opp / 10

10* Tan(65) = Opp

21.445 = Opp

so the height of the tree is approx Β 21.4 feet ( to the nearest 10th )

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