
Answer:
7.5 mol of AlCl₃ will produce.
Explanation:
Given data:
Mass of chlorine = 779 g
Moles of aluminium chloride = ?
Solution:
Chemical equation:
2AlBr₃ + 3Cl₂ → 2AlCl₃ + 3Br₂
Number of moles of Clâ‚‚:
Number of moles = mass/ molar mass
Number of moles = 779 g / 71 g/mol
Number of moles = 11.3 mol
Now we will compare the moles of chlorine with AlCl₃ .
            Cl₂    :    AlCl₃
             3     :     2
            11.3    :    2/3×11.3 = 7.5 mol