Given the following balanced redox reaction: 2 KMnO,+16 HCI2KCI+2 MnCl, +8 H20+5 Cl What is the stoichiometric factor relating KM O, and MnCl, representing the actual numbers of moles of each species that react and are produced according to the equation above?

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Answer:

The stoichiometric factor relating KMnO4 and MnCl is 1:1

Explanation:

The complete equation is

[tex]16HCl + 2KMnO_{4}   →    5Cl_{2} + 2MnCl_{2} + 2KCl + 8H_{2} O[/tex]

Any chemical equiation can be read in terms of moles. In this equiation, 6 moles of hydrochloric acid react with 2 moles of potassium permanganate to produce 2 moles of manganese(II) chloride.

As can be seen, two moles of the permanganate produce two moles of the chloride, then the stoichiometric factor is 1 to 1.